Problem 6 is really trivial and there’s not a lot to say.
The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
Here go you.
def sum_square_difference(limit):
sum_of_squares = sum(x * x for x in range(1, limit + 1))
square_of_sum = sum(range(1, limit + 1)) ** 2
return square_of_sum - sum_of_squares
This calculates the answer of 25164150 in 2ms.